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Solution — 2017 Question 6 Normal Distribution

Let X be the height, in m, of a randomly chosen adult male.

$ ParseError: Can't use function '$' in math mode at position 1: $̲ X \sim \mathrm{N} \left( \mu, \sigma^2 \right)

\begin{align*} \mathrm{P}\left(X < 1.6\right) &= 0.2 \\ \mathrm{P}\left(Z < \frac{1.6 - \mu}{\sigma}\right) &= 0.2 \\ \frac{1.6 - \mu}{\sigma} &= -0.841\,62 \end{align*}$$ ParseError: {align*} can be used only in display mode.

[apply standardization and inverse norm to find mu/sigma]

\begin{align*} \mathrm{P}\left(X > 1.75\right) &= 0.3 \\ \mathrm{P}\left(Z > \frac{1.75 - \mu}{\sigma}\right) &= 0.3 \\ \frac{1.75 - \mu}{\sigma} &= 0.524\,40 \end{align*}$$

[apply standardization and inverse norm to find mu/sigma]

Cross-multiplying and rearranging,

\begin{align*} \mu - 0.8416\sigma &= 1.6 \tag{1} \end{align*}$$

\begin{align*} \mu + 0.5244\sigma &= 1.75 \tag{2} \end{align*}$$

Solving (1) and (2) with a GC, μ=1.6924,σ=0.10981

\begin{align*} \text{Mean} &= 1.6924 \\ &= 1.69\; \QED \text{ (to 3 s.f.)} \end{align*}$$

\begin{align*} \text{Variance} &= 0.109\,81^2 \\ &= 0.0121\; \QED \text{ (to 3 s.f.)} \end{align*}$$

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