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Solution — 2023 Question 11 Sampling| Hypothesis Testing

(a)
Unbiased estimate of population mean=x‾=∑(x−15)n+15=25.550+15=15.51
Unbiased estimate of population variance=s2=1n−1(∑(x−15)2−(∑(x−15))2n)=150−1(26.4−(25.5)250)=0.27337

Let X denote the random variable of the distance (in m) thrown by a child in region A
Let μ denote the population mean distance (in m) thrown by a child in region A

H0:μ=15.4
H1:μ>15.4

Under H0, X‾∼N(15.4,0.27337250) Z=X‾−15.40.27337250∼N(0,1) approximately by the Central Limit Theorem since n=50 is large

From GC,
p-value = 0.068420>0.05⇒Do not reject H0

Hence there is insufficient evidence at the 5% level of significance to conclude whether the mean distance thrown has increased after taking Pedro’s course ∎

(b)

H0:μ=15.4
H1:μ>15.4

Under H0, X‾∼N(15.4,0.5250) Z=X‾−15.40.5250∼N(0,1) approximately by the Central Limit Theorem since n=50 is large

Since the null hypothesis is rejected,

x‾−15.40.550≤−1.6449orx‾−15.40.550≥1.6449x‾≤15.2∎x‾≥15.6∎
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Parts

  • Part (a)
  • Part (b)