Equating the two equations,
kx+k=k−1+3kx−x2x2−2kx+1=0
For the line to intersect the curve at two distinct points,
b2−4ac>0(−2k)2−4(1)(1)>04k2−4>0k2−1>0(k+1)(k−1)>0
k<−1∎ork>1∎