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Exponential & Logarithmic Functions

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Solution — 2024 Question 5 Exponential & Logarithmic Functions| Simultaneous Linear Equations| Differentiation & Applications| Integration & Applications

(a)

Let b, c and d denote the number of bedside, console and dining tables produced each month respectively.

b=3(c+d)b−3c−3d=0(1)

bedside is 3 times console and dining combined

d=c+29c−d=−29(2)

29 more dining than console

b+c+d=156(3)

total tables

Solving equations (1), (2) and (3) with a GC,

b=117,c=5,d=34

solution to the system of equations

The factory produces 117 bedside tables, 5 console tables and 34 dining tables each month. ∎

(b)

When t=5.5,

S=600(1.2−0.3e1−0.1t)=600(1.2−0.3e1−0.1(5.5))=600(1.2−0.3e0.45000)=437.70=438∎ (to 3 s.f.)
(c)

When S=500,

600(1.2−0.3e1−0.1t)=500

Dividing by 600 and rearranging,

310e1−0.1t=1130e1−0.1t=119ln⁡e1−0.1t=ln⁡1191−0.1t=ln⁡1190.1t=−ln⁡119+1t=−10ln⁡119+10=7.9933=7.99∎ (to 3 s.f.)
(d)
S=600(1.2−0.3e1−0.1t)dSdt=600(0.03e1−0.1t)=18e1−0.1t∎

Since e1−0.1t>0 for all t, we have dSdt>0 for all t≥0.

This means that S is always increasing for t≥0, i.e. the model indicates that the rate of CO2 emissions will always be increasing over time. ∎

(e)
∫03600(1.2−0.3e1−0.1t)dt=600∫03(1.2−0.3e1−0.1t)dt=600[1.2t+3e1−0.1t]03=600(1.2(3)+3e1−0.1(3)−(1.2(0)+3e1−0.1(0)))=892∎ (to 3 s.f.)

It represents the total CO2 emissions (in tonnes) over the first 3 years.

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Parts

  • Part (a)
  • Part (b)
  • Part (c)
  • Part (d)
  • Part (e)