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Probability
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Solution —
2016
Question 7
Probability
(a)
(b)
(i)
P
(
A
∪
B
)
=
P
(
A
)
+
P
(
B
)
−
P
(
A
∩
B
)
=
0.6
+
0.25
−
0.05
=
0.8
∎
(ii)
P
(
exactly one of
A
and
B
)
=
P
(
A
∪
B
)
−
P
(
A
∩
B
)
=
0.8
−
0.05
=
0.75
∎
(c)
P
(
A
|
B
′
)
=
P
(
A
∩
B
′
)
P
(
B
′
)
=
0.55
0.75
=
11
15
∎
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2017 Q11