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Solution —
2021
Question 2
Differentiation & Applications
|
Integration & Applications
(a)
y
=
(
2
x
3
−
5
x
1
3
)
2
=
4
x
6
−
20
x
10
3
+
25
x
2
3
d
y
d
x
=
24
x
5
−
200
3
x
7
3
+
50
3
x
−
1
3
=
24
x
5
−
200
3
x
7
3
+
50
3
x
1
3
∎
(b)
∫
1
5
−
4
x
d
x
=
∫
(
5
−
4
x
)
−
1
2
d
x
=
−
(
5
−
4
x
)
1
2
2
+
c
∎
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2022 Q2