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Solution — 2021 Question 2 Differentiation & Applications| Integration & Applications

(a)
y=(2x3−5x13)2=4x6−20x103+25x23dydx=24x5−2003x73+503x−13=24x5−2003x73+503x13∎
(b)
∫15−4xdx=∫(5−4x)−12dx=−(5−4x)122+c∎
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