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Solution — 2021 Question 6 Normal Distribution

Let X be the height of a randomly chosen plant, in metres.

X∼N(μ,σ2)

P(X>1.72)=0.3P(Z>1.72−μσ)=0.31.72−μσ=0.52440

apply standardization and inverse norm to find mu/sigma

P(X<1.52)=0.1P(Z<1.52−μσ)=0.11.52−μσ=−1.2816

apply standardization and inverse norm to find mu/sigma

Cross-multiplying and rearranging,

μ+0.5244σ=1.72(1)
μ−1.2816σ=1.52(2)

Solving (1) and (2) with a GC, μ=1.66∎,σ=0.111∎

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